If p(x) = 2x²-x3 + x + 2 then find p (o)
P(x) = 2x² - x3 + x + 2
p (□) = 2x0²-□^3+0+2
= 2x0-□+0+2
=□.
plz give correct answer..
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Answer:
- p(x) = 2x²-x3 + x + 2 then find p (o)
- p(x) = 2x²-x3 + x + 2 then find p (o)P(x) = 2x² - x3 + x + 2
- p(x) = 2x²-x3 + x + 2 then find p (o)P(x) = 2x² - x3 + x + 2p (□) = 2x0²-□^3+0+2
- p(x) = 2x²-x3 + x + 2 then find p (o)P(x) = 2x² - x3 + x + 2p (□) = 2x0²-□^3+0+2= 2x0-□+0+2
- p(x) = 2x²-x3 + x + 2 then find p (o)P(x) = 2x² - x3 + x + 2p (□) = 2x0²-□^3+0+2= 2x0-□+0+2=□.
Answered by
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Answer:
0
Step-by-step explanation:
P(x) = 2x² - x3 + x + 2
p (0) = 2x0²-0^3+0+2
= 2x0-0+0+2
=0
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