Math, asked by abdulrehan2830, 9 months ago

If P(x) = √3 x²-3x+2 find the
value of P(√3)​

Answers

Answered by jk1997
0

answer:

2

Step-by-step explanation:

P(x) = √3 x²-3x+2

p(√3)=√3(√3)² -3(√3)+2

        = 3√3-3√3+2

        =2

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Answered by AlluringNightingale
2

Answer:

p(√3) = 2

Note:

★ If the expression for a polynomial p(x) is given , then to fine p(a) we just need to put x = a every where in the expression of p(x) .

Solution:

Given : p(x) = √3x² - 3x + 2

To find : p(√3) = ?

Now,

We have ,

p(x) = √3x² - 3x + 2

Let's find p(√3) on putting x = √3 everywhere in the expression of p(x) .

Thus,

=> p(x) = √3x² - 3x + 2

=> p(√3) = √3•(√3)² - 3•(√3) + 2

=> p(√3) = 3√3 - 3√3 + 2

=> p(√3) = 2

Hence,

The required value of p(3) is 2 .

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