Question

If p(x) =3x^2+4, then find the values of p(-4) and p(1)​

Answer 1

$\huge{\blue{\fbox{\purple{\bigstar{\mathbf{\red{Solution}}}}}}}$

$\rule{200}3$

• $\orange{\mathbb{Given}}$ : p(x) = 3x² + 4

★$\sf\pink{Taking\: p(-4)}$

=> 3(-4)² + 4

=> 3(16) + 4

=> 48 + 4

=> 52

★$\sf\pink{Taking\: p(1)}$

=> 3(1)² + 4

=> 3 + 4

=> 7

$\rule{200}3$

Answer 2

Answer:

The answer is -

P(-4) = 52

P(1) = 7

Step-by-step explanation:

To find the values of p(-4) and p(1), if p(x) = 3$x^{2}$ + 4

Now, substitute the values x = -4 and x = 1 in the polynomial p(x) = 3$x^{2}$ + 4

So,

p(x) = 3$x^{2}$ + 4

p(-4) = 3$(-4)^{2}$ + 4

        = 3(16) + 4

        = 48 + 4

p(-4) = 52

And,

p(x) = 3$x^{2}$ + 4

p(1) = 3$(1)^{2}$ + 4

      = 3 + 4

p(1) = 7

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