Question

if p(x) =3x^4-5x^3+x^2+8 find the value of P(-1)

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Answer 1

Answer:

The value of $p(-1)=3x^{4}-5x^{3}+x^{2} +8$ is 17.  

Step-by-step explanation:

The value of p(-1) can be by substituting the x in p(x) with x=-1.

$p(x)=3x^{4}-5x^{3}+x^{2} +8$

$p(-1)=3(-1)^{4}-5(-1)^{3}+(-1)^{2} +8$

$p(-1)=3(1)-5(-1)+(1) +8$

$p(-1)=3+5+1 +8$

$p(-1)=17$

Hence the value of p(-1) when $p(x)=3x^{4}-5x^{3}+x^{2} +8$ is 17.