Question

If p(x)=3x³+4x²-5x+8 then find p(-2),p(1),p(0)​

Answer 1

p(-2) =3×-8+4×4+5×2+8 =-24+16+10+8 =-24+24+8=8

p(1)=3+5-5+8=3+8=11

p(0)=0+0-0+8=8

Answer 2

1)p(-2)

3(-2)^3+4(-2)^2-5(-2)+8=

3×(-8)+4×4+10+8

-24+16+10+8

-24+34 =10

2)p(1)

3(1)^3+4(1)^2-5(1)+8=0

3+4-5+8=0

15-5=10

3)p(0)=3(0)^3+4(0)^2-5(0)+8=8