Question

if p(x)= 3y^3 +y^2 +2y+1 . find the value of p(0) p(2).​

Answer 1

Step-by-step explanation:

p(y)=3y³+y²+2y+1

p(0)=3(0)³+(0)²+2(0)+1=0+0+0+1=1

p(2)=3(2)³+(2)²+2(2)+1=24+4+4+1=33