Question

if P (x) = 4x^5- 3x- 5x^3 + x^2-8 then find P (-1)​

Answer 1

Step-by-step explanation:

if P (x) = 4x^5- 3x- 5x^3 + x^2-8

then P (-1) = 4(-1)^5- 3(-1)- 5(-1)^3 + (-1)^2-8

= - 4 + 3 + 5 + 1 - 8

= -3

Answer 2

$\huge\boxed{\boxed{\fcolorbox{white}{pink}{Answer}}}$

$↪ \mathbb{P(x)= 4{x}^{5}-3x-5{x}^{3}+{x}^{2}-8}$

$↪ \mathbb{P(x)= 4{x}^{5}-5{x}^{3}+{x}^{2}-3x-8}$

$\mathcal\pink{Substituting\: the\: value\: in\: P(x)\: as\: -1}$

$↪ \mathbb{P(-1)= 4{-1}^{5}-5{-1}^{3}+{-1}^{2}-3(-1)-8}$

$↪ \mathbb{P(-1)= -4+5+1+3-8}$

$↪ \mathbb{P(-1)= (-3)}$

Hope it helps úh