Question

If p(x) = ax^3 – 3x^2 + 5x – 36 has (x – 4) as its factor, then the value of a is


urgent plz​

Answer 1

x-4 is a factor for p(x)

so,x=4 subs in p(x)

a(4)³-3(4)²+5(4)-36=0

64a-48+20-36=0

64a-64=0

64a=64

a=1

Answer 2

Answer:

hope it is helpful mark in brainiest