Question

If P(x) = ax^4+bx^3+cx^2+dx+e has roots at x = 1, 2, 3, 4 and P(0) = 48, what is P(5)?

A. 48
B. 24
C. 0
D. 50; If P(x) = ax^4+bx^3+cx^2+dx+e has roots at x = 1, 2, 3, 4 and P(0) = 48, what is P(5)?; A. 48; B. 24; C. 0; D. 50

Answer 1

here is ur answer

hope this helps

answer is a

Answer 2

HERE IS YOUR ANSWER. ..

PUT P (x) as

a (x -1 ) (x -2)(x-3)(x-4)

P (0) = a (-1)(-2)(-3)(-4)

a × 24 = 48

a = 2


P (x) = 2 (x-1 )( x-2) (x-3) (x-4)

P (5) = 2 (4)(3)(2)(1)

P (5) = 48 ..

HOPE IT HELPS YOU! !!!