Question

If p (x) = ax? + bx + c and a + b + c = 0, then a zero in (a) (b) (c) (d) none of these

Answer 1

Step-by-step explanation:

P(x)=ax2+bx+c

Hence, for real roots,

b2−4ac≥0

Q(x)=−ax2+dx+c

Hence, for real roots,

d2+4ac≥0

Now, 

ac=0

Now if ac<0

Then,

b2−4ac>0

Hence, P(x).Q(x) has atleast 2 real roots .

If ac>0

Then

d2+4ac>0

Hence, P(x).Q(x) has atleast 2 real roots .