Question

If p(x) = ax + bx + c and a + b + c=
zero,then one of the zero is
(a)-b/a
(b)c/a
(c)-c/a
(d) none of these
Pls explain the answer ​

Answer 1

Answer:

P(x) = ax^2 + bx + c

Put x = 1

P(1) = a +b+c

But, a + b + c = 0

Therefore, P(1) = 0

X = 1

Answer 2

Step-by-step explanation:

b) c/a

Step-by-step explanation:

ax2+bx = -c

a+b = -c

therefore ax2 + bx = a + b

by observation you can see that x=1 is a solution

since product of roots = c/a, the second root is c/a

hope it is understand

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