If p(x) = ax²+ bx + c, and a +b+c= 0, then one zero
Answers
Answered by
7
Answer:
x=1 is one of the zero of p(x) .
Step-by-step explanation:
Given p(x)=
The above mentioned equation is in the quadratic form
a+b+c =0
Consider the given eqn
p(x)=
The above mentioned equation is the general form of the polynomial where a, b, c are variables and x is a constant
Put x=1 in the above equation we get
p(1)=a+b+c
But we know that a+b+c = 0
Therefore p(1)=0
So when x=1 p(1)=0
Therefore x=1 is the root of p(x)
x=1 is one of the zero of p(x)
Here p represents the polynomial
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Answered by
17
GIVEN
- p(x) = ax²+ bx + c
- a +b+c= 0
TO FIND
ONE ZERO OF p(x)
CALCULATION
Now
So
So by Remainder Theorem 1 is a zero of p(x)
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