Question

If p(x) = ax²+ bx + c, and a +b+c= 0, then one zero​

Answer 1

Answer:

x=1 is one of the zero of p(x) .

Step-by-step explanation:

Given p(x)=

The above mentioned equation is in the quadratic form

a+b+c =0

Consider the given eqn

p(x)=

The above mentioned equation is the general form of the polynomial where a, b, c are variables and x is a constant

Put x=1 in the above equation we get

p(1)=a+b+c

But we know that a+b+c = 0

Therefore p(1)=0

So when x=1 p(1)=0

Therefore x=1 is the root of p(x)

x=1 is one of the zero of p(x)

Here p represents the polynomial

HEY MATE IF YOU LIKE MY ANS PLS MARK ME AS BRINLIEST...

Answer 2

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

GIVEN

• p(x) = ax²+ bx + c
• a +b+c= 0

TO FIND

ONE ZERO OF p(x)

CALCULATION

$p(x) = ax²+ bx + c$

Now

$p(1) = a \times (1)²+ b \times (1) + c = a + b + c \: = 0$

So

$p(1) = 0$

So by Remainder Theorem 1 is a zero of p(x)