Question

If p(x) = ax²+bx+c, write the sum and product of zeroes​

Answer 1

Answer:

Step-by-step explanation:

let the zeros be ∝ andβ so

∝+β=-b/a

∝β=c/a

a-numerical coefficient of x²

b-numerical coefficient of x

c-constant

Answer 2

$\mathtt{p(x) = ax²+bx+c}$

$\texttt{Let α \& β be the zeroes of p(x).}$

$\texttt{Then,}$

$\mathtt{(α+β) = \Large\frac{- coefficient \; of \; x}{coefficient \; of \; x²} \normalsize = \Large\frac{-b}{a}}$

$\mathtt{(αβ) = \Large\frac{coefficient \; of \; constant \; term}{coefficient \; of \; x²} \normalsize = \Large\frac{c}{a}}$