if p(x) is dividend (ax-b) is divisior what is the remainder
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When p(x) is divided by ax+b, then what is the remainder?
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When p(x) is divided by (ax + b), let the quotient be Q(x) and remainder be R (Since divisor ax + b is linear, R will be a constant).
Since Dividend = Quotient * Divisor + Remainder, we get
p(x) = Q(x) * (ax + b) + R, which is an identity true for values of x, in particular for x = - b/a.
Setting x = ( - b/a),
p( -b/a) = R.
Remainder is, therefore, equal to p( -b/a).
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