Question

if p( x) is equal to 2x cube +a x square + 3 x minus 3 and f (x) is equal to x cube + x square - 4 x + a leave the same remainder when divided by x minus 2 find the value of a​

Answer 1

Step-by-step explanation:

$p(x) = 2 {x}^{3} + a {x}^{2} + 3x - 3 \\ f(x) = {x}^{3} + {x}^{2} - 4x + a$

given that the remainders are same when divided by x-2.

x=2

substituting this in p(x) and f(x)

$2( {2})^{3} + a {(2)}^{2} + 3(2) - 3 = {(2)}^{3} + {(2)}^{2} - 4(2) + a \\ = 16 + 4a + 6 - 3 = 8 + 4 - 8 + a \\ = 4a - a = 4 - 19 \\ 3a = - 15 \\ a = - 5$

Answer 2

answer is 1 by 6

Step-by-step explanation:

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