Question

if p(x) = x^100 + ax + k is divisible by x^2-x then find value of a

Answer 1

Answer:

a=(-1)

Step-by-step explanation:

p(x)= x^100+ax+k

let g(x)=x^2-x

=x(x-1). =>x=0,1

p(x) is exactly divisible by g(x)

put x=0 in p(x)

p(0)= (0)^100+a(0)+k=0

0+0+k=0

k=0

p(1)=1^100+a(1)+k=0

1+a+0=0

a=(-1)

Answer 2

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