Question

If p(x) = x^2 - 2√2 + 1 , then find p(2√2).

Answer 1

p(x)=x²-2√2 +1

let x=2√2

p(2√2)=(2√2)²-2√2+1

=8-2√2+1

=9-2√2

Answer 2

hey mate here is your answer .

(x)=x^2-2V2 + 1

p(2V2) = (2V2)^2 - 2V2 +1

= 2V2×2V2 -2V2 +1

= 4×2-2V2+1

= 8 +1 - 2V2

= 9-2V2

HOPE IT HELPS YOU!

mark this answer as brainiest.