Question

if p(x)=x^2-2√2+1,then find the value of p(2√2)

Answer 1

$\textbf {Question}$ :

If p(x) = x^2 - 2√2x + 1, then find the value of p(2√2).

$\textbf {Answer}$ :

Given that,

$p(x) = {x}^{2} - 2 \sqrt{2} x + 1 \\ \\ p(2 \sqrt{2} ) = {(2 \sqrt{2} )}^{2} - 2 \sqrt{2} \times (2 \sqrt{2} ) + 1\\ \\ p(2 \sqrt{2} ) = 8 - 8 + 1 \\ \\ p(2 \sqrt{2} ) = 1$

Thus, p(2√2) = 1.

Answer 2

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