Question

please answer this question

Answer 1

We know that the latent heat of vaporization of ammonia is 341 cal/g.
So the hfg will be 341*4.18=1425.38 kJ/kg
Now,
m*1425.38=2*4.18*(293-273)
or, m= 0.1173 kg
or, m= 117.3 gm!