Question

If p(x)= x

2 – 2√2x+1, then find the value of p(2√2)​

Answer 1

p(x)=x²-2√2x+1.

p(2√2)=(2√2)²-(2√2*2√2)+1

p(2√2)=(2√2)²- (2√2)²+1

=0+1.

=1.

Therefore, the answer is 1.

Thank you.

Hope this will help you.

Second type

p ( x ) = x² - 2√2x + 1

p ( 2√2 ) = ( 2√2 )² - ( 2√2 × 2√2 ) + 1

p ( 2√2 ) = ( 8 ) - ( 8 ) + 1

p ( 2√2 ) = 1