if p(x)=x^2-2x,then value of p(2)
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Given, p(x) = x2 – 2√2x + 1 …(i)
On putting x = 2√2 in Eq. (i), we get
P(2√2) = (2√2)2– (2√2)(2√2) + 1 = 8 - 8 + 1 = 1
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