if p( x) = x^2+7x-9, find the value of p(2) + p(-1)
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Answered by
71
Answer:
Refer to the attachment for the answer.
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Answered by
4
❥ - 6
P( x ) = x ² + 7x - 9
➻ P ( 2 ) = ( 2 ) ² + 7 ( 2 ) - 9
= 4 + 14 - 9
= 18 - 9
= 9
➻ P ( - 1 ) = ( -1 ) ² + 7 ( -1 ) - 9
= 1 - 7 - 9
= 1 - 16
= - 15
Value of P( 2 ) + P ( - 1 )
➻ ( 9 ) + ( - 15)
➻- 6
Hence, your answer is - 6
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Answered by
5
❥ - 6
P( x ) = x ² + 7x - 9
➻ P ( 2 ) = ( 2 ) ² + 7 ( 2 ) - 9
= 4 + 14 - 9
= 18 - 9
= 9
➻ P ( - 1 ) = ( -1 ) ² + 7 ( -1 ) - 9
= 1 - 7 - 9
= 1 - 16
= - 15
Value of P( 2 ) + P ( - 1 )
➻ ( 9 ) + ( - 15)
➻- 6
Hence, your answer is - 6
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Answered by
6
❥ - 6
P( x ) = x ² + 7x - 9
➻ P ( 2 ) = ( 2 ) ² + 7 ( 2 ) - 9
= 4 + 14 - 9
= 18 - 9
= 9
➻ P ( - 1 ) = ( -1 ) ² + 7 ( -1 ) - 9
= 1 - 7 - 9
= 1 - 16
= - 15
Value of P( 2 ) + P ( - 1 )
➻ ( 9 ) + ( - 15)
➻- 6
Hence, your answer is - 6
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