if p(x)=x^3+2x^2+5x+7. find p(0),p(1),p(2),p(3),p(4)
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Answered by
0
Answer: ur required answer ;-
when p(x) = x³ +2x² +5x +7
i) → p(0) = 0³ + 2 (0)² +5 × 0 + 7
⇒ 7 .
ii) p(1) = 1³ + 2(1)² + 5 ×1 + 7
⇒ 15 .
iii) p(2) = 2³ + 2 (2)² + 5 × 2 + 7
⇒ 8 + 8 +10 + 7
⇒ 33 .
iv) p(3)= 3³ + 2 (3)² + 5 × 3 +7
⇒ 76.
Step-by-step explanation: hope this will help u mate , need feedback plz ,
itz akansha .
DARK QUEEN ....
Answered by
2
Answer:
p(0) = 7
p(1) = 15
p(2) = 33
p(3) = 67
p(4) = 123
Step-by-step explanation:
p(0) = 0³ + 2(0)² + 5(0) + 7
=> 0 + 0 + 0 + 7 => 7
p(1) = 1³ + 2(1)² + 5(1) + 7
=> 1 + 2 + 5 + 7 => 15
p(2) = 2³ + 2(2)² + 5(2) + 7
=> 8 + 2(4) + 10 + 7
=> 8 + 8 + 10 + 7 => 33
p(3) = 3³ + 2(3)² + 5(3) + 7
=> 27 + 2(9) + 15 + 7
=> 27 + 18 + 15 + 7 => 67
p(4) = 4³ + 2(4)² + 5(4) + 7
=> 64 + 2(16) + 20 + 7
=> 64 + 32 + 20 + 7 => 123
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