Question

If p(x)= x^3- 2x^2 -x + 2 = (x + 1)(x - 2)(x - d) then what is the value of d? ​

Answer 1

Answer:

-1

Step-by-step explanation:

the terrm independent of x in lhs=2

so term independent of x in rhs=2

term independent of x in rhs=1*(-2)*d=2

=>d=-1

Answer 2

Answer:

1

Step-by-step explanation:

(x-1)/x3-2x2-x+2=(x2-x-2)

(x-1)(x2-x-2)

(x-1)(x2+x-2x-2)

(x-1)(x(x+1)-2(x+1))

(x-1)(x-2)(x+1)

on comparing,

x+1= in rhs x+1

x-2= in rhs x-2

x-1=x-d

therefore, d=1