If p (X)=x^3-32x^2+5x-3, find P (5), P(1) P(1/2).
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Step-by-step explanation:
for the given values of 'x' u need replace it
- P(x)=x^3-32x^2+5x-3
- P(5)= (5P)^3 - 32(5)^2 +5(5) - 3
= 125 - 800 + 25 - 3
= -653
- P(x)=x^3-32x^2+5x-3
- P(1)= (1)^3 - 32(1)^2 + 5(1) - 3
= 1 - 32 +5 -3
= -29
- P(x)=x^3-32x^2+5x-3
- P(1/2)= (1/2)^3 - 32(1/2)^2 + 5(1/2) - 3
- = 1/8 - 8 + 5/2 - 3
- = 1/8 + 5/2 -11
- = 20/8 - 11
- = 68/8 or 17/2
hope the solution helps you
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