Math, asked by Ritsu36757, 2 months ago

if p(x)= x^3-3x^2+2x-3 find the value of p(1)+ p(-1)​

Answers

Answered by chemistrywala
0

P(1) = (1)³-3(1)²+2(1)-3

P(-1)= (-1)³-3(-1)²+2(-1)-3

P(1)+P(-1)== -3-3-6 === -12

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