Question

if p(x)=x^3+3x^2-2x+4, then find the value of p(2) + p(-2) -p(0)​

Answer 1

Answer:

28

Step-by-step explanation:

p(2)=8+12-4+4=20

p(-2)=-8+12+4+4=12

p(0)=+4

So, p(2)+p(-2)-p(0)

=20+12-4

=32-4

=28

Answer 2

Answer:

p(x) =x^3+3x^2-2x+4

p(2)= 8+12-4+4 = 20

p(-2)= -8+12+4+4=12

p(0)=0+0-0+4= 4

p(2)+p(-3)- p(0)

=20+12-4

=28