Math, asked by bijis25, 8 months ago

if p(x)=x^3-4x^2+×+6 then show that p(3)=0 and hence factorize p(x)​

Answers

Answered by yashaswini3679
2

p(x) =  x^3 - 4 x^2 +x+6

p(3) =  3^3 -4 × 3^2 + 3 + 6

= 27 - 36 + 9

= 0

HOPE THIS ANSWER HELPS U....

Answered by Anonymous
8

Step-by-step explanation:

p(x) =  {x}^{3}  - 4 {x}^{2}  + x + 6

p(0) =  {0}^{3}  - 4 \times  {0}^{2}  + 0 + 6

p(0) = 6

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