Question

if p(x)=x^3-mx^2-x+6 is divisible by g(x)=x-2. find the value m

Answer 1

Answer:

see the attachment for the answer

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Answer 2

m is equal to 3

Step-by-step explanation:

p(x) = $x^3 - mx^2 - x + 6$

g(x) = x - 2

Let's have g(x) = 0

⇒ x - 2 = 0

⇒ x = 2

Now, for p(2) = $2^3 - m2^2 -2 + 6 = 0$

⇒ 8 - 4m - 2 + 6 = 0

⇒ 4m = 12

⇒ m = 3