Question

if p(x)=x cube -ax square +bx +3 leaves a remainder -19 when divided by x+2 and a remainder 17 when divided by (x-2) ,prove that a+b=6.​

Answer 1

Answer:

$p(x) =x {}^{3} + ax {}^{2} + bx$

r (x)=-19,17 g (x)=x+2,x-2

W.K.T

p (x)=g (x)×q (x)+r(x)

x^3+ax^2+bx=x+2×q (x)-19

2a-b=q (x)-19+2

2a-b=q (x)-17

2)x^3+ax^2+bx=×-2×17

x^2+x (a+2)-17=0

sorry I am not available for this question.

Answer 2

Answer:

Step-by-step explanation:

W