if p(x) = x-x+1 find p(0) p(1), and p(2) values
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☘️ Required Solution:-
p(x) = x - x + 1
putting x = 0
→ p(0) = 0 - 0 + 1
→ p(0) = 1
p(x) = x - x + 1
putting x = 1
→ p(1) = 1 - 1 + 1
→ p(1) = 1
p(x) = x - x + 1
putting x = 2
→ p(2) = 2 - 2 + 1
→ p(2) = 1
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