Question

please solve this problem​

Answer 1

Answer:

Reena will pay interest of ₹18, 000

Ruchitra will pay interest of ₹ 66,550

ruchitra will paid more interest by ₹48,550

Answer 2

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★ Given :

Reema borrowed (principal) = Rs. 60,000

Ruchira borrowed (principal) = Rs. 50,000

Reema and Ruchira's time period = 3 years

Reema paid simple interest of 10 %

Ruchira paid compound interest of 10 %

★ To find :

Who paid more interest and how much?

★ Method :

× Reema's simple interest on the given data

• Simple interest = P × T × R /100

• Simple interest = 60000 × 3 × 10 /100

• Simple interest = 18,000

± Reema's paid interest = Rs. 18000

× Ruchira's Compound interest on the given data

• Amount = P (1 + R/100)^N

• Amount = 50000 ( 1 + 10/100)³

• Amount = 50000 × 110/100 × 110/100 × 110/100

• Amount = 66,550

• Compound interest = Amount - Principal

• Compound interest = 66550 - 50000

• Compound interest = 16,550

± Ruchira's paid interest = Rs. 16550

★ Answer :

Reema paid more interest.

To find how much more = Subtract it

18000 - 16550 = 1,450

She paid Rs. 1450 more interest than Ruchira.

$\color{pink}{THANK YOU!}$