If p(x)= x + x² + V5x + V5, find the value of p(- V5). pls answer this question is from ncert class 9
Answers
Answered by
0
Step-by-step explanation:
p(x)= x+x^2+√5x+√5
then , x+ √5= 0
x=-√5
p(-√5)=√5+(-√5)^2 + √5(-√5) + √5
= -√5 + 5 - 5 + √5
p(-√5) = 0 answer
Answered by
5
Heya mate, 0 is ur answer..............
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