Question

If p(x) = x2 – 1 and q (x) = 5 (x minus 1), which expression is equivalent to (p – q)(x)?
5(x – 1) – x2 – 1
(5x – 1) – (x2 – 1)
(x2 – 1) – 5(x – 1)
(x2 – 1) – 5x – 1

Answer 1

(x2-1)-5 (x-1)

Step-by-step explanation:

(p-q)(x)=p (x)-q (x)=(x2-1)-5 (x-1) ans

Answer 2

(p - q) (x) = (x² - 1) - 5 (x - 1)

Step-by-step explanation:

The given expressions are

p (x) = x² - 1

q (x) = 5 (x - 1)

Now (p - q) (x)

= p(x) - q(x)

= (x² - 1) - 5 (x - 1)

∴ the equivalent expression for (p - q) (x) is (x² - 1) - 5 (x - 1).

Note: To solve this tyoe of problems, simply put the expression for the functions in terms of variables and calculate algebraically by using algebraic operations [addition (+), subtraction (-), etc].

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