Question

If p(x)= x2 - 11x + 30 then 1/alpha + 1/beeta =

Answer 1

Answer: Zeroes of polynomial are -5 and -6.

Step-by-step explanation:

Since we have given that

x^2+11x+30

We first find the roots of the above quadratic equation:

x^2+11x+30=0\\\\x+6x+5x+30=0\\\\x(x+6)+5(x+6)=0\\\\(x+5)(x+6)=0\\\\x=-5,-6

Let α = -5 and β = -6

Now, we will verify the relationship between zeroes and coefficient of polynomial:

\alpha +\beta =\dfrac{-b}{a}\\\\-5-6=\dfrac{-11}{1}\\\\-11=-11

Similarly,

\alpha\beta =\dfrac{c}{a}\\\\-5\times -6=\dfrac{30}{1}\\\\30=30

Hence, verified.

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