If P(x) = x² = √2x+1 then p(√z) is equal to
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Answered by
1
Answer:
1
Step-by-step explanation:
p(x)=x²-2√2x+1.
p(2√2)=(2√2)²-(2√2*2√2)+1
p(2√2)=(2√2)²- (2√2)²+1
=0+1.
=1.
Let us also try another method you so can be more sure
p ( x ) = x² - 2√2x + 1
p ( 2√2 ) = ( 2√2 )² - ( 2√2 × 2√2 ) + 1
p ( 2√2 ) = ( 8 ) - ( 8 ) + 1
p ( 2√2 ) = 1
HOPE IT HELPS YOU!!!
Answered by
45
p ( x ) = x² - 2√2x + 1
p ( 2√2 ) = ( 2√2 )² - ( 2√2 × 2√2 ) + 1
p ( 2√2 ) = ( 8 ) - ( 8 ) + 1
p ( 2√2 ) = 1
hope it helps :)
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