if p(x)=x2_3x+2 find p(_1)
Answers
Answered by
1
p(X) = x²-3x+2
p(1) = (1)²-3(1)+2
= 1-3+2=0
p(1) = (1)²-3(1)+2
= 1-3+2=0
Answered by
2
answer :
p(1)=(-1)^2-3(-1)+2
p(1)=1+3+2
p(1)= 6
hope it helps
p(1)=(-1)^2-3(-1)+2
p(1)=1+3+2
p(1)= 6
hope it helps
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