Question

if p[x] = x²-4x +2 ,evalvate p[2] - p[-1] + p[1/2]

Answer 1

Answer:

Step-by-step explanation:

p[2]=2^2-4x2+2=4-4+2=2

p[-1]=-1^2-4x-1-1+2=1-4-1=-3-1=-4

p[1/2]=1/2^2-4x1/2+2=1/4-2+2=-8/4+2=1/2+2=2.5

p[2]-p[-1]+p[1/2]=2-4+2.5=-2+2.5=1/2

Answer 2

Answer:21/4

Step-by-step explanation:

Given that, p(x) =x²-4x+8.

Thus, p(2) =2²-4(2)+8= 4

p(-1) =1²-4(1)+8= 5

p(1/2) =(1/2)²-4(1/2)+8= 25/4

Now,

p(2)-p(-1)+p(1/2)=4-5+25/4

=21/4.