If p(x)= x²-4x+3 , evaluate p(2)-p(-1)+p(1)
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p(1)=1^2-4(1)+3
=0
p(-1)=(-1)^2-4(-1)+3
=8
p(2)=2^2-4(2)+3
=(-1)
=0
p(-1)=(-1)^2-4(-1)+3
=8
p(2)=2^2-4(2)+3
=(-1)
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