Math, asked by sucessarch, 9 months ago

if p(x)=x²-4x+3 evaluate p(x)-p(-1)​

Answers

Answered by Anonymous
3

Answer:

P(x)=x²-4x+3

so,

p(2)= 2²-4×2+3= 4-8+3= (-1)

p(-1)= (-1)²-4(-1)+3= 1+4+3= 8

p(1/2)= (1/2)²-4(1/2)+3= (1/4)-2+3 =1/4+1 =5/4

now,

p(2)+p(-1)-p(1/2)

=(-1)+8-5/4

=7-5/4

=28-5/4

=23/4

Step-by-step explanation:

hope \: it \: helped \: you \: friend

Answered by rsagnik437
20

p(x)=x²-4x+3

Then,p(x)=x²-4x+3

p(-1)=(-1)²-4(-1)+3

=>1+4+3

=>8

p(x)-p(-1)

=>x²-4x+3-8

=>x²-4x-5

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