If p(x) = x2 – 5x + 1 , evaluate p(0) .
Answers
Answered by
1
Step-by-step explanation:
P(x) =x^2-5x+1
P(2)=put x=2 I.e
= (2^2)-5(2)+1
P(2) = -5
P(-1)=put x= -1 I.e
= (-1)^2 - 5(-1)+1
P(-1) =5
P(1/3) = put x = 1/3 I.e
=(1/3^2) - 5(1/3) +1
P(1/3) =-5/9
P(2)-p(-1)+p(1/3) =- 95/9 = - 10.555
Answered by
0
Answer:
(0)2–5(0)+1
0+0+1
1
P(x) =1
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