Math, asked by Saurab9066, 1 month ago

If p(x) = x2 – 5x + 1 , evaluate p(0) .​

Answers

Answered by sujaykatoch100
1

Step-by-step explanation:

P(x) =x^2-5x+1

P(2)=put x=2 I.e

= (2^2)-5(2)+1

P(2) = -5

P(-1)=put x= -1 I.e

= (-1)^2 - 5(-1)+1

P(-1) =5

P(1/3) = put x = 1/3 I.e

=(1/3^2) - 5(1/3) +1

P(1/3) =-5/9

P(2)-p(-1)+p(1/3) =- 95/9 = - 10.555

Answered by sharmaankit2751
0

Answer:

(0)2–5(0)+1

0+0+1

1

P(x) =1

Similar questions