Question

if p(x) = x²-5x-6. find the values of p(-1),p(-2),p(0),.p(2),p(3)​

Answer 1

Answer:

p(-1) = (-1)²-5(-1)-6

= 1+5-6 = 0

p(-2)= (-2)²-5(-2)-6 = 4+10-6 = 8

p(0)= (0)²-5(0)-6 = -6

p(2)= 2²-5(2)-6 = 4-10-6 = -12

p(3)= 3²-5(3)-6 = 9-15-6 = -12