Math, asked by Bindupriyaregunta, 1 month ago

If p(x)=x2-5x-6 the value of find p(0),p(1),p(2),p(3)?​

Answers

Answered by tanishka386
1

Answer:

p(0)= -6

p(1)= -10

p(2)= -12

p(3)=-12

Answered by mohan7007331
40

Answer:

p(x)=x²-5x-6

value for p(0)

p(0)=0²-5×0-6

p(0)=0-0-6

p(0)=-6

value for p (1)

p(1)=1²-5×1-6

p(1)=1-5-6

p(1)=1-11

p(1)= 10

Value for p (2)

p(2)=2²-5×2-6

p(2)=4-10-6

p(2)=4-16

p(2)=-12

value for p(3)=

p(3)=3²-5×3-6

p(3)=9-15-6

p(3)=9-21

p(3)=-12

Hope it helps you ✌️✌️

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