If p(x)=x2-5x-6 the value of find p(0),p(1),p(2),p(3)?
Answers
Answered by
1
Answer:
p(0)= -6
p(1)= -10
p(2)= -12
p(3)=-12
Answered by
40
Answer:
p(x)=x²-5x-6
value for p(0)
p(0)=0²-5×0-6
p(0)=0-0-6
p(0)=-6
value for p (1)
p(1)=1²-5×1-6
p(1)=1-5-6
p(1)=1-11
p(1)= 10
Value for p (2)
p(2)=2²-5×2-6
p(2)=4-10-6
p(2)=4-16
p(2)=-12
value for p(3)=
p(3)=3²-5×3-6
p(3)=9-15-6
p(3)=9-21
p(3)=-12
Hope it helps you ✌️✌️
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