Question

If p(x)=x²-5x -6, then find the values of p(1),p(2),po), p(-1).p(-3).​

Answer 1

Answer:

• Hey mate here is the ans

Step-by-step explanation:

p(1)=-11

p(2)=-12

p(0)=-6

p(-1)=-4

p(-3)=18

Hope it helps u plz follow and mark me as brainliest.

Answer 2

Step-by-step explanation:

put x=1 if p(1)

p(x)=x^2-5x-6

p(1)= (1)^2-5(1)-6

=1-5-6

=-11

then

p(2)=(2)^2-5(2)-6

=4-10-6

=-12

p(0)=0-0-6

=-6

p(-1)=(-1)^2-5(-1)-6

=1+5-6

=0

p(-3)=(-3)^2-5(-3)-6

= 9 +15-6

=18