Question

if p(x)=x2- x+1 find p(1),p(-1),p(0)​

Answer 1

Step-by-step explanation:

p (1) = (1)^2-(1)+1

1-1+1

1

P (-1) = (-1)^2-(-1)+1

1+1+1

3

p (0)=(0)^2-(0)+1

0-0+1

1

just put the values of x

Answer 2

The values of p(1), p(-1), and p(0) are 1, 3, and 1 respectively.

Given:

The function p(x) = x²- x+1.

To Find:

p(1), p(-1), and p(0)​.

Solution:

We have been given a quadratic equation p(x) = x²- x+1. Note that since 'x' can take any value, x is the independent variable here. We have to find the value of the function when x takes values 1, -1, and 0.

i) At x = 1,

  p(1) = 1² - 1 + 1 = 1

ii) At x = -1

   p(-1) = (-1)² - (-1) + 1 = 1 + 1 + 1 = 3

⇒ p(-1) = 3

iii) At x = 0

   p(0) = 0² - 0 + 1 = 1

⇒ p(0) = 1.

Hence, the values of p(x) at x = 1, -1, and 0 are 1, 3, and 1 respectively.

∴ The values of p(1), p(-1), and p(0) are 1, 3, and 1 respectively.

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