Math, asked by agrima59, 1 year ago

using identity find the product (2x-y+3z)(x²+y²+9z²+2xy+3xy-6zx²)​

Answers

Answered by Anonymous
4

Answer.....

(2x-y+3z)(4x²+y²+9z²+2xy+3yz-6xz)

(2x-y+3z((2x)²(y)²+(3z)²-(-y*2x)-(-y*3z)-(2x*3z)

(2x)³+(-y)³+(3z)³-(3×-y×2x×3z)

(a+b+c)(a²+b²+c²-ab-bc-ca)=

a³+b³+c³-3abc

8³-y³+27+³+18xyz

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