Question

if p(x)=x²+x+1 find (x+1) p(x) -(x-1) p(x) ​

Answer 1

Answer:

x+1=0

x=-1

(-1)^2+(-1)+1

1-1+1=1

Answer 2

Step-by-step explanation:

( x - 1) p(x) - ( x- 1) p(x)

(x- 1) (x²+x + 1 ) - ( x- 1) ( x²+ x +1 )

[ x( x²+ x + 1 ) - 1 ( x²+ x +1 ) ] - [ x ( x²+ x + 1) -1 ( x²+ x+1) ]

[ x³ + x² +x -x² - x - 1 ] - [ x³+x² + x -x²- x- 1]

x³-1 - ( x³-1 )

x³- 1 - x³ + 1

=0