Question

IF P(x)= x3 -1 Find the value of P (1), P (-1) , P(0), P(2), P (-2) ?​

Answer 1

Step-by-step explanation:

$P(1) = {1}^{3} - 1 = 1 - 1 = 0 \\ P( - 1) = { - 1}^{3} - 1 = - 1 - 1 = - 2 \\ P(0) = {0}^{3} - 1 = - 1 \\ P(2) = {2}^{3} - 1 = 8 - 1 = 7 \\ P( - 2) = { - 2}^{3} - 1 = - 8 - 1 = - 10$

Answer 2

Answer:

If p(x) =x3-1,

X= 1, - 1, 0, 2, - 2

Step-by-step explanation:

P( x ) = x3 - 1

P( 1.) =( 1)3-1

= 1-1

= 0

P(1)=0

P(-1)=(-1)3-1

=1-1

=.0

P(-1)..=.0

P(0)=(0)3-1

=0-1

=-1

P(0)=-1