If p(x) = x³-1, then find P(1) and P(-1)?
maths
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Answer:
p(1)=0, p(-1)=-2
Step-by-step explanation:
p(1)=1³-1
1-1{1³=1}
0
p(-1)=-1³-1
-1-1{-1³-1}
-2
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