Question

if p(x) =x³-1 then the value of p(1)+ p(-1) is ____​

Answer 1

$\large\sf\underline{Given\::}$

• p ( x ) = $\sf\:x^{3} -1$

‎

$\large\sf\underline{To\:find\::}$

• p ( 1 ) + p ( - 1 )

‎

$\large\sf\underline{How\:to\:do\:?\::}$

In this question we are given p ( x ) as $\sf\:x^{3} -1$. We are asked to find p ( 1 ) + p ( - 1 ). So at first we will calculate p ( 1 ) by substituiting x as 1 in p ( x ) and then we will calculate p ( - 1 ) by substituiting p ( x ) as p ( - 1 ) . After that we would find their sum and would end up getting our final answer. Let's begin !

‎

$\large\sf\underline{Solution\::}$

$\large{\mathfrak{1^{st}\:step\:-}}$

Let's Calculate p ( 1 ) first :

So p ( x ) = $\sf\:x^{3} -1$

$\sf\implies\:p(1)=(1)^{3} - 1$

$\sf\implies\:p(1)=1- 1$

$\sf\implies\:p(1)=\cancel{1}- \cancel{1}$

$\small\fbox\red{\:p\:(1)\:=\:0}$ ★

=====================

‎

$\large{\mathfrak{2^{nd}\:step\:-}}$

Let's Calculate p ( - 1 ) now :

So p ( x ) = $\sf\:x^{3} -1$

$\sf\implies\:p(-1)=(-1)^{3} - 1$

$\sf\implies\:p(-1)=-1- 1$

$\small\fbox\red{\:p\:(1)\:=\:-2}$ ★

=====================

‎

$\large{\mathfrak{3^{rd}\:oR\:Final\:step\:-}}$

Let's calculate the sum of p ( 1 ) and p ( - 1 ) :

$\sf\to\:p(1)+p(-1)$

$\sf\to\:0+(-2)$

$\sf\to\:0-2$

$\small{\underline{\boxed{\mathrm\green{\to\:-2}}}}$ ⍟

=====================

‎

$\dag\:\underline{\sf So\:the\:required\:value\:is\:-2.}$

‎

‎

!! Hope it helps !!

Answer 2

-2 is ur answer

_____________